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Pay close attention to how the consecutive terms are related.
Recursive Rule: a_1 = 6, a_2 = 1, a_n=a_(n-1) + a_(n-2) Next two terms: 38, 61
ccccc a_2+a_1&=& 1+6 &=& 7 [1.2em] a_3+ a_2&=& 7+ 1 &=& 8 [1.2em] a_4+ a_3&=& 8+ 7&=& 15 [1.2em] a_5+ a_4&=& 15+ 8&=& 23 [2em] ... & & ... & & ...
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a_(n-1)+a_(n-2) = a_n |
We can see above that the sum of the consecutive terms equals the next term. Therefore, to obtain the value of the term in the n^(th) position, we need to add two previous terms. With this information and knowing that the first term equals 6 and the second term equals 1, we can write the recursive formula. a_1=6, a_2 = 1 and a_n=a_(n-1) + a_(n-2) We will write the next 2 terms of a sequence now. ccccc ... & & ... & & ... [1.2em] a_6+a_5&=& 23+15 &=& 38 [1.2em] a_7+a_6&=& 38+23&=& 61