Big Ideas Math Integrated I, 2016
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Big Ideas Math Integrated I, 2016 View details
6. Recursively Defined Sequences
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Exercise 16 Page 317

Pay close attention to how the consecutive terms are related.

Recursive Rule: a_1 = 1, a_2 = 1, a_n=a_(n-1) - a_(n-2) Next three terms: 0, - 1, - 1

Practice makes perfect
We want to write a recursive formula for the given sequence. 1, 1, 0, - 1, - 1, 0, 1, 1, ... To do so we need to analyze how the consecutive terms are related. Let's find the difference between each pair of consecutive terms.

ccccc a_2-a_1&=& 1-1 &=& 0 [1.2em] a_3- a_2&=& 0- 1 &=& - 1 [1.2em] a_4- a_3&=& - 1- 0&=& - 1 [1.2em] a_5- a_4&=& - 1-( - 1)&=& [1.2em] a_6-a_5&=& -(- 1)&=& 1 [1.2em] a_7-a_6&=& 1- &=& 1 [2em] ... & & ... & & ...

a_(n-1)-a_(n-2) = a_n

We can see above that the difference of the consecutive terms equals the next term. Therefore, to obtain the value of the term in the n^(th) position, we need to subtract two previous terms. With this information and knowing that the first term equals 1 and the second term also equals 1, we can write the recursive formula. a_1=1, a_2 = 1 and a_n=a_(n-1) - a_(n-2) We will write the next 3 terms of a sequence now. ccccc ... & & ... & & ... [1.2em] a_8- a_7&=& 1- 1 &=& 0 [1.2em] a_9- a_8&=& 0- 1 &=& - 1 [1.2em] a_(10)- a_9&=& - 1- 0&=& - 1