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Pay close attention to how the consecutive terms are related.
Recursive Rule: a_1 = 5, a_2 = 6, a_n=a_(n-1) + a_(n-2) Next three terms: 45, 73, 118
ccccc a_2+a_1&=& 6+5 &=& 11 [1.2em] a_3+ a_2&=& 11+ 6 &=& 17 [1.2em] a_4+ a_3&=& 17+ 11&=& 28 [2em] ... & & ... & & ...
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a_(n-1)+a_(n-2) = a_n |
We can see above that the sum of the consecutive terms equals the next term. Therefore, to obtain the value of the term in the n^(th) position, we need to add two previous terms. With this information and knowing that the first term equals 5 and the second term equals 6, we can write the recursive formula. a_1=5, a_2 = 6 and a_n=a_(n-1) + a_(n-2) We will write the next 3 terms of a sequence now. ccccc ... & & ... & & ... [1.2em] a_5+ a_4&=& 28+ 17 &=& 45 [1.2em] a_6+a_5&=& 45+28 &=& 73 [1.2em] a_7+a_6&=& 73+45&=& 118