Exercise 3 Page 242

The solution of the system of the linear equations is the point where the graphs intersect. From the graph, we can tell that this point is (0,1).

Let's check this solution by substituting the point into both equations.

y=1 & (I) y=2x+1 & (II)

(I), (II):x= 0, y= 1

1=1 1? =2( 0)+1

ZeroPropMult

(II): Zero Property of Multiplication

1=1 1=1

Since both equations hold true after substituting the point, we can confirm that (0,1) is a solution for the system of equations.