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Big Ideas Math Integrated I, 2016

BI

Big Ideas Math Integrated I, 2016 View details

Cumulative Assessment

Finish the assignment

Exercise 7 Page 269

Practice makes perfect

a We can substitute the x=-2 into the equation and solve for a.

ax-8=4-x

x= -2

a( -2)-8=4-( -2)

Multiply

-2a-8=4-(-2)

a-(- b)=a+b

-2a-8=4+2

Add terms

-2a-8=6

LHS+8=RHS+8

-2a=14

.LHS /(-2).=.RHS /(-2).

a=-7

When a=-7, the solution is x=-2.

b We can substitute the x=12 into the equation and solve for a.

ax-8=4-x

x= 12

a( 12)-8=4- 12

Multiply

12a-8=4-12

Subtract term

12a-8=-8

LHS+8=RHS+8

12a=0

.LHS /12.=.RHS /12.

a=0

When a=0, the solution is x=12.

c We can substitute the x=3 into the equation and solve for a.

ax-8=4-x

x= 3

a( 3)-8=4- 3

Multiply

3a-8=4-3

Subtract term

3a-8=1

LHS+8=RHS+8

3a=9

.LHS /3.=.RHS /3.

a=3

When a=3, the solution is x=3.

Subchapter links

Exercises p.268-269