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Big Ideas Math Integrated I, 2016 View details

Chapter Review

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Exercise 22 Page 210

Begin by finding the residuals.

Scatter Plot:

Is it a good fit? Yes

Practice makes perfect

Let's first recall the model given in the example. y=0.50x-23.5

We will verify whether it is a good fit for the data by making a scatter plot of the residuals. We will begin by finding the residuals.

Height, x	Shoe size, y	y=0.50x-23.5	y-value from the model	Residual
64	9	0.50( 64)-23.5	8.5	9-8.5=0.5
62	7	0.50( 62)-23.5	7.5	7-7.5=-0.5
70	12	0.50( 70)-23.5	11.5	12-11.5=0.5
63	8	0.50( 63)-23.5	8	8-8=
72	13	0.50( 72)-23.5	12.5	13-12.5=0.5
68	9.5	0.50( 68)-23.5	10.5	9.5-10.5=-1
66	9	0.50( 66)-23.5	9.5	9-9.5=-0.5
74	13.5	0.50( 74)-23.5	13.5	13.5-13.5=
68	10	0.50( 68)-23.5	10.5	10-10.5=-0.5
59	6.5	0.50( 59)-23.5	6	6.5-6=0.5

Now, we can make the scatter plot.

As we can see, the points are evenly dispersed about the horizontal axis. Therefore, the equation y=0.50x-23.5 is a good fit.

Subchapter links

1 Writing Equations in Slope-Intercept Form p.208

2 Writing Equations in Point-Slope Form p.208

3 Writing Equations of Parallel and Perpendicular Lines p.209

4 Scatter Plots and Lines of Fit p.209

5 Analyzing Lines of Fit p.210

6 Arithmetic Sequences p.210

Exercise 22 Page 210

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