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When a point with coordinates (x,y) is rotated 90^(∘) clockwise about the origin, the coordinates of its image are (- y,x).
Let's first graph the polygon ABC with the given vertices.
Rotations About the Origin | ||
---|---|---|
90^(∘) Rotation | 180^(∘) Rotation | 270^(∘) Rotation |
ccc Preimage & & Image [0.5em] (x,y) & → & (y,- x) |
ccc Preimage & & Image [0.5em] (x,y) & → & (- x,- y) |
ccc Preimage & & Image [0.5em] (x,y) & → & (- y,x) |
We want to rotate a triangle 90^(∘) counterclockwise about the origin. A rotation by 90^(∘) counterclockwise ends up in the same place as a rotation by 270^(∘) clockwise. Therefore, we can use the coordinate changes shown in the table that correspond to a 270^(∘) clockwise to determine the coordinates of the image of each vertex. ccc Preimage & & Image (x,y) & → & (- y, x) [0.5em] A(- 3,- 1) & & A'(1,- 3) [0.5em] B(2,2) & & B'(- 2,2) [0.5em] C(3,- 3) & & C'(3,3) We can now plot the obtained points and draw the image of the given triangle after the rotation!