Exercise 1 Page 55

When we are asked for the root of a number, we are typically being asked for the principal root. When the index is even, this is the positive root. Since the index of - sqrt(16) is even, let's find its principal root.

- sqrt(16)

SplitIntoFactors

Split into factors

- sqrt(2*2*2*2)

a * a * a * a=a^4

- sqrt(2^4)

SqrtPowToNumber

sqrt(a^2)=a

- 2

The real root of - sqrt(16) is - 2.