Big Ideas Math Geometry, 2014
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Big Ideas Math Geometry, 2014 View details
1. Similar Polygons
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Exercise 18 Page 424

Begin by finding the perimeter of the backyard. Then using Perimeters of Similar Polygons — Theorem 8.1 — find the perimeter of the patio.

Perimeter of Backyard: 130feet
Perimeter of Patio: 52feet

Practice makes perfect

We want to put a rectangular patio in our backyard similar to the shape of our backyard. We have been told that our backyard is 45 feet long and 20 feet wide. Our new patio will be 18 feet long. This can be modeled in the following diagram.

We want to find the perimeters of the patio and backyard. Let's start with the perimeter of the backyard.

Perimeter of the Backyard

We know that the perimeter of a rectangle is twice the length plus twice the width of the rectangle. Since we know the length and width of the backyard, we can find its perimeter, P_B, as follows.

P_B&=2(45)+2(20) &=130 Therefore, the perimeter of the backyard is 130 feet.

Perimeter of the Patio

To find the perimeter of the patio, we will first recall Perimeters of Similar Polygons, Theorem 8.1.

Perimeters of Similar Polygons

If two polygons are similar, then the ratio of their perimeters is equal to the ratios of their corresponding side lengths.

Since the length of the patio corresponds to the length of the backyard, using this theorem we can write the following proportion. P_P/130=18/45 Next, we will solve the proportion for P_P to find the perimeter of the patio.
P_P/130=18/45
P_P=2 340/45
P_P=52
Thus, the perimeter of the patio is 52 feet.