Big Ideas Math Geometry, 2014
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Big Ideas Math Geometry, 2014 View details
3. Proving That a Quadrilateral Is a Parallelogram
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Exercise 8 Page 380

Find the slope of each side and compare it with the slope of its corresponding opposite side. Also, find and compare the midpoint of each diagonal.

See solution.

Practice makes perfect

Let's show that the quadrilateral ABCD below is a parallelogram.

We will use two different methods – using the definition and using the Parallelogram Diagonals Converse.

Method 1

By definition, a parallelogram is a quadrilateral with both pairs of opposite sides parallel. Then, let's find the slopes of each side of ABCD. m = y_2-y_1/x_2-x_1Let's begin by finding the slope of AB.
m = y_2-y_1/x_2-x_1
m_1 = 5- 3/2-( -3)
Simplify right-hand side
m_1 = 5-3/2+3
m_1 = 2/5
The computations of the remaining slopes are summarized in the table below.
Endpoints m = y_2-y_1/x_2-x_1 Slope
B(2,5) and C(5,2) m_2 = 2-5/5-2 m_2 = -1
C(5,2) and D(0,0) m_3 = 0-2/0-5 m_3 = 2/5
D(0,0) and A(-3,3) m_4 = 3-0/-3-0 m_4 = -1

As we can see, m_1 = m_3 and m_2=m_4, which implies that AB∥ CD and BC∥ AD. Therefore, ABCD is a parallelogram.

Method 2

In this part, we will draw the diagonals of the parallelogram.

Our mission here is to check that the midpoint of AC is also the midpoint of BD because this will prove that the diagonals intersect each other at their midpoints. M = (x_1+x_2/2,y_1+y_2/2 ) Let's substitute the coordinates of A(-3,3) and C(5,2) to find its midpoint.
M_1 = (x_1+x_2/2,y_1+y_2/2 )
M_1 = (-3+ 5/2,3+ 2/2 )
Simplify
M_1 = (2/2,5/2 )
M_1 = (1,2.5)
Similarly, let's substitute the coordinates of B(2,5) and D(0,0).
M_2 = (x_1+x_2/2,y_1+y_2/2 )
M_2 = (2+ 0/2,5+ 0/2 )
Simplify
M_2 = (2/2,5/2 )
M_2 = (1,2.5)
As we can see, M_1=M_2 which means that both diagonals have the same midpoint. Consequently, they intersect each other at their midpoints. This is equivalent to say that P is the midpoint of each diagonal.

Since the diagonals bisect each other, by the Parallelogram Diagonals Converse, we conclude that ABCD is a parallelogram.