Exercise 37 Page 206

To solve an equation, we should gather all of the variable terms on one side of the equation and all of the constant terms on the other side, using the Properties of Equality.

5x+16=-3 x

AddEqn

LHS+3x=RHS+3x

5x+16+3x=-3 x+3x

AddTerms

Add terms

8x+16=0

SubEqn

LHS-16=RHS-16

8x+16-16=0-16

SubTerms

Subtract terms

8x=-16

DivEqn

.LHS /8.=.RHS /8.

8x/8=-16/8

CalcQuot

Calculate quotient

x=-2

The solution to the equation is x=-2. We can check our solution by substituting it into the original equation.

5x+16=-3 x

Substitute

x= -2

5( -2)+16? =-3 ( -2)

▼

Simplify

MultPosNeg

a(- b)=- a * b

-10+16? =-3 (-2)

AddTerms

Add terms

6? =-3 (-2)

MultNegNegOnePar

- a(- b)=a* b

6=6

Since the left-hand side is equal to the right-hand side, our solution is correct.