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If the ratios of consecutive y-values are equal, then the data can be modeled by an exponential function. If the difference of consecutive y-values is constant, then the data can be modeled by a linear function.
Exponential relationship of data: Yes.
Example model: y=12.95(1.85)^x
Explanation: See solution.
We want to determine whether the data show an exponential relationship. Then we will write a function that models the data. Let's do those things one at a time.
If the ratios of consecutive y-values are equal, then the data can be modeled by an exponential function. If the difference of consecutive y-values is constant, then the data can be modeled by a linear function. Consider the given table.
x | -3 | -1 | 1 | 3 | 5 |
---|---|---|---|---|---|
y | 2 | 7 | 24 | 68 | 194 |
7-2&= 5, 24-7= 17, 68-24&=44, 194-68=126 We can see that the differences are not constant, so the data cannot be modeled by a linear function. Let's determine the ratios of the consecutive y-values. 2/7 &≈ 0.286, 7/24 ≈ 0.292, [0.8em] 24/68 &≈ 0.353 , 68/194 ≈ 0.351 Each ratio is around 0.3, so the data can be modeled by an exponential function. y=ab^x
x= 1, y= 24
a^1=a
a* a=a^2
.LHS /7.=.RHS /7.
sqrt(LHS)=sqrt(RHS)
Use a calculator
Rearrange equation