From the diagram, we see that f(x) passes through (- 2,- 2) and (2,0). By substituting the x-coordinates of these points into the function, we can determine if this is the case.
We cannot calculate the square root of a negative number. Therefore, the function does not pass through this point. Let's do the same thing for the second point.
When x=0, the function's y-value is - 2. Therefore, the function does not go through (2,0) either.
Drawing the Correct Graph
To draw the graph correctly, we should first find the lower limit of the domain. As already explained, the radicand has to be non-negative, so by setting it equal to zero we can find the domain's lower limit.
x-2=0 ⇔ x=2
When we know the lower limit of the domain, we can find its corresponding y-value.
