Exercise 1 Page 537

We will solve the given equation by taking the square roots, because it has the form of ax^2+c=0. Therefore, we will start by isolating x^2 on one side of the equation. Remember we need to consider the positive and negative solutions.

x^2 - 121 = 0

AddEqn

LHS+121=RHS+121

x^2 = 121

SqrtEqn

sqrt(LHS)=sqrt(RHS)

x= ± sqrt(121)

CalcRoot

Calculate root

x= ± 11

We found that x=± 11. Therefore, there are two solutions for the equation x=11 and x=- 11.

Checking Our Answer

Checking our answer

We can check our answers by substituting them for x in the given equation. Let's start with x=- 11.

x^2-121=0

Substitute

x= - 11

( - 11)^2-121? =0

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Simplify

NegBaseToPosBase

(- a)^2=a^2

11^2-121? =0

CalcPow

Calculate power

121-121? =0

SubTerm

Subtract term

0=0 ✓

Since 0=0, we know that x=- 11 is a solution of the equation. Let's check if x=11 is also a solution.