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One method is by using the point and slope that we can identify from the point-slope form.
See solution.
Let's recall the point-slope form of a linear function. y- y_1= m(x- x_1) Here m is the slope and ( x_1, y_1) is a point on the line. We will now explore two methods to graph a line given in point-slope form.
y- y_1&= m(x- x_1) [0.8em] y- 1&= 3/2(x- 4) We identified the point ( 4, 1) and a slope of 32. Recall that the slope is the change in y divided by the change in x. m= 3/2 ⇓ Δ y/Δ x= 3/2 We will now first plot the point ( 4, 1). Then we will, as indicated by the slope, take a step of 2 units to the right and 3 units up to find a second point.
By drawing a line through the points we have our graph.
x= 8
Subtract term
a/c* b = a* b/c
Calculate quotient
LHS+1=RHS+1