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The perimeter of any triangle is the sum of the lengths of its three sides. Since the given triangle is isosceles, two of its sides have the same length. Let's call the length of each congruent side $x$ and the third unknown side $y.$ Now, we can write the expression representing the perimeter of the given triangle.
$\begin{gathered}
2x+y
\end{gathered}$
We are told that the perimeter is *at most* $12$ inches which means that the perimeter is *less than or equal to* $12.$
$\begin{gathered}
2x + y \leq 12
\end{gathered}$
It is given that $x={\color{#0000FF}{5}}.$ Let's substitute this value into the inequality and solve for $y.$
This inequality tells us that the length of the remaining side must be less than or equal to $2$ cm. Note that lengths are always positive, so the more precise way to express the possible lengths is by writing the following inequality.
$\begin{gathered}
0< y\leq 2
\end{gathered}$
The length of the remaining side must be greater than $0$ cm and less than or equal to $2$ cm.

$2x + y \leq 12$

Substitute$x={\color{#0000FF}{5}}$

$2\cdot{\color{#0000FF}{5}} + y \leq 12$

MultiplyMultiply

$10 + y \leq 12$

SubIneq$\text{LHS}-10\leq \text{RHS}-10$

$y \leq 2$