Sign In
| 13 Theory slides |
| 13 Exercises - Grade E - A |
| Each lesson is meant to take 1-2 classroom sessions |
Here are a few recommended readings before getting started with this lesson.
A coordinate system is a reference framework used to describe the positions of objects like points, lines, and surfaces in a space. A fixed point called the origin is used as a reference in the coordinate system. The most common types of coordinate systems are one-, two-, or three-dimensional.
A coordinate plane is a two-dimensional coordinate system. It is a grid that results from intersecting a vertical number line with a horizontal number line at their zero points. The horizontal number line is usually named the x-axis and the vertical number line is usually the y-axis.
A coordinate is the position of an object in a coordinate system relative to the corresponding axis. Coordinates are often seen together with other coordinates, which can describe the position of an object in a coordinate system with one, two, three, or even more dimensions.
In a two-dimensional coordinate system, points are usually expressed as a coordinate pair — also called an ordered pair — denoted by (x,y). The first coordinate states the position along the x-axis and the second coordinate states the position along the y-axis.
Identify the coordinates of the given point. Write the coordinates as an ordered pair (x,y), where x represents the x-coordinate and y the y-coordinate.
Dominika plays basketball with her friends every afternoon. She warms up by running and picks up two friends, Jordan and Emily, on the way to the court. Dominika uses ordered pairs to represent the positions of her and her friends' houses.
Position | |
---|---|
Dominika's House | D=(2,1) |
Jordan's House | J=(2,4) |
Emily's House | E=(-1,4) |
Moving one unit on the x-axis or y-axis on the coordinate plane is counted as moving one block. Since Dominika can only stay on the straight roads, her position can only move up, down, left, and right on the graph.
Moving one unit on the x-axis or y-axis on the coordinate plane is the same as Dominika moving one block. Dominika only runs on the straight roads, so her progress on the graph can only move in four directions — up, down, left, and right.
Keeping this in mind, one route she can take is moving five blocks directly to the right. Move 5 units to the right starting her house to show this possible destination. Remember that Dominika's house is located at (2,1), not the origin!
Another spot Dominika might go is one block up and four blocks to the right of her starting point. It does not matter if she moves up on her first, second, third, fourth, or final move. Her destination will always be the same if she moves one block up out of the five total moves.
Follow the same reasoning to find the other places that Dominika can go. Plot each as ordered pairs on the coordinate plane.
Now that all the points are plotted on the graph, connect them with lines to see the overall shape.
The shape is a rotated square.
The places Dominika can go can be determined by identifying all the possible routes she can take. Remember, she can only go five blocks away from her home. Moving left or down indicates a negative direction on the corresponding axis, represented by negative numbers.
Route from Home | Calculations | Destination |
---|---|---|
5 blocks to the right | (2+5,1) | (7,1) |
4 blocks to the right and 1 block up | (2+4,1+1) | (6,2) |
3 blocks to the right and 2 blocks up | (2+3,1+2) | (5,3) |
2 blocks to the right and 3 blocks up | (2+2,1+3) | (4,4) |
1 block to the right and 4 blocks up | (2+1,1+4) | (3,5) |
5 blocks up | (2,1+5) | (2,6) |
1 block to the left and 4 blocks up | (2−1,1+4) | (1,5) |
2 blocks to the left and 3 blocks up | (2−2,1+3) | (0,4) |
3 blocks to the left and 2 blocks up | (2−3,1+2) | (-1,3) |
4 blocks to the left and 1 block up | (2−4,1+1) | (-2,2) |
5 blocks to the left | (2−5,1) | (-3,1) |
4 blocks to the left and 1 block down | (2−4,1−1) | (-2,0) |
3 blocks to the left and 2 blocks down | (2−3,1−2) | (-1,-1) |
2 blocks to the left and 3 blocks down | (2−2,1−3) | (0,-2) |
1 block to the left and 4 blocks down | (2−1,1−4) | (1,-3) |
5 blocks down | (2,1−5) | (2,-4) |
1 block to the right and 4 blocks down | (2+1,1−4) | (3,-3) |
2 blocks to the right and 3 blocks down | (2+2,1−3) | (4,-2) |
3 blocks to the right and 2 blocks down | (2+3,1−2) | (5,-1) |
4 blocks to the right and 1 block down | (2+4,1−1) | (6,0) |
In a coordinate plane, the intersection of the x-axis and the y-axis produces four regions called quadrants. The quadrants are numbered counterclockwise from the top right quadrant as Quadrant I to Quadrant IV in the bottom right.
The signs of the coordinates of a point can be determined based on which quadrant the point lies in.
A coordinate system has four quadrants that provide information about the signs of the x- and y-coordinates of a point. In the following applet, identify in which quadrant the given point lies.
Look at the signs of the coordinates of each point to identify their quadrants.
Point | Signs of Coordinates | Quadrant |
---|---|---|
(-2,-8) | (−,−) | Quadrant III |
(4,-2) | (+,−) | Quadrant IV |
(-11,3) | (−,+) | Quadrant II |
(4,3) | (+,+) | Quadrant I |
Reflecting a point means making a mirror image of that point by flipping it across a certain line or axis. The following rules show how to find reflected points across a specific axis.
Point | Axis of Reflection | Procedure | Reflected Point |
---|---|---|---|
(x1,y1) | x | Change the y-coordinate to its opposite. | (x1,-y1) |
(x1,y1) | y | Change the x-coordinate to its opposite. | (-x1,y1) |
(x1,y1) | x and y | Change the x- and y-coordinates to their opposites. | (-x1,-y1) |
Next, the process for reflecting points across the x-axis, the y-axis, or both, on a coordinate plane will be shown. Consider the points A, B, and C.
Point | Axis of Reflection | Reflected Point |
---|---|---|
A=(5,8) | x | ? |
B=(10,-5) | y | ? |
C=(-4,-7) | x and y | ? |
Once each initial point and its reflection across a given axis are found, plot both points on the coordinate plane.
Dominika's team is only one game away from winning the basketball tournament! Dominika is a shooting guard and wants to use her math skills to improve her game. She starts by figuring out the point on the court from where she usually scores using a coordinate plane. This point is (-4,-3).
Dominika is interested in the mirror point of (-4,-3) because it is a great shooting position. This point is as far away from the basket as the original point but is oriented in a different direction. This can give her an advantage over her opponents and help her score more points during game!
Now that Dominika understands her attack and defense positions better, she can perform much better on the court. Her team is doing great and they keep scoring point after point until before they know it, they win first place in the tournament. They are the champions!
This lesson showed how to locate points with respect to the x- and y-axis on a coordinate plane. A third axis, usually called the z-axis, can be used to provide more information about the position of objects. Think of it like this.
Description | |
---|---|
x-axis | Tells if something is in front of or behind the origin. |
y-axis | Tells if something is to the left or right of the origin |
z-axis | Tells if something is above or below the origin. |
These three axes create a 3D coordinate system that is similar to the coordinate plane but with the addition of an extra dimension. This additional dimension means that points are represented as ordered triples (x,y,z) instead of as ordered pairs, as in the coordinate plane.
Let's figure out which reflections were used on the point with coordinates ( a, b) to get to the given points. This could help us determine the quadrant to which each option belongs.
Let's look at point ( a, - b). Point&Reflected Point ( a, b)&( a, - b) Notice how these two points share the same x-coordinate but have opposite y-coordinates. Remember, when we keep the x-coordinate the same and change the y-coordinate to its opposite, we are reflecting the point across the x-axis. Point&Reflection Acrossx-axis ( a, b)&( a, - b) If the starting point is in Quadrant II, its reflection across the x-axis ( a, - b) is in the quadrant below, which is Quadrant III.
Now let's find the quadrant of point ( - a, b). Point&Reflected Point ( a, b)&( - a, b) These two points share the same y-coordinate but have opposite x-coordinates. Remember that if we change the x-coordinate to its opposite while keeping the y-coordinate the same, the point will be reflected across the y-axis. Point&Reflection Acrossy-axis ( a, b)&( - a, b) Since the initial point is in Quadrant II, its reflection across the y-axis ( - a, b) is in Quadrant I.
Finally, let's look at the point ( - a, - b). Point&Reflected Point ( a, b)&( - a, - b) Here, we can observe that the reflected point has both coordinates opposite to the initial coordinates. This implies that point ( a, b) is reflected across both the x- and y-axes. Point&Reflection Acrossx- andy-axes ( a, b)&( - a, b) Let's apply one reflection at a time. When reflecting the point across the x-axis, the point falls in Quadrant III. After that, when reflecting the new point across the y-axis, the point lands in Quadrant IV. This means that the point ( -a, -b) belongs to Quadrant IV.
Now that we have determined the quadrant to which each point belongs, let's organize our information.
Ordered Pair | Quadrant |
---|---|
(a,- b) | Quadrant III |
(- a, b) | Quadrant I |
(- a,- b) | Quadrant IV |
Magdalena is sketching a rectangle on a coordinate plane and has already drawn three of its corners.
Let's look at the given diagram.
The point (-4, -2) in Quadrant III is the reflection of the point (-4, 2) in Quadrant II over the x-axis. Similarly, let's reflect the point (2,2) in Quadrant I over the x-axis. We can do this by changing its y-coordinate to its opposite. Point&Reflection Acrossx-axis ( 2, 2)&( 2, -2) Therefore, the missing corner has coordinates ( 2, -2).
We multiply the length and width of a rectangle to find its area. Area of the Rectangle Length*Width Let's count the number of units horizontally from point (-4, -2) to (2, -2) to find the length of the rectangle. Next, let's count the units vertically from point (-4, -2) to (-4, 2) to find its width.
The length of the rectangle is 6 and its width is 4. Let's multiply these two values to find the area of the rectangle. Area of the Rectangle 6* 4=24 The area of the rectangle is 24 square units.