Sign In
| Student Learning Objectives: |
|---|
|
| | 16 Theory slides |
| | 13 Exercises - Grade E - A |
| | Each lesson is meant to take 1-2 classroom sessions |
In the following applet, points A, B, C, and D, are movable. Arrange them as desired, then use the slider bar to rotate the points around the central point P.
| PA | PA' | ||
|---|---|---|---|
| PB | PB' | ||
| PC | PC' | ||
| PD | PD' |
This time, use the slider bar to rotate triangle ABC about point P.
| m ∠ APA' | |
|---|---|
| m ∠ BPB' | |
| m ∠ CPC' |
A rotation is a transformation in which a figure is turned about a fixed point P. The number of degrees the figure rotates α ^(∘) is the angle of rotation. The fixed point P is called the center of rotation. Rotations map every point A in the plane to its image A' such that one of the following statements is satisfied.
Rotations are usually performed counterclockwise unless stated otherwise.
Rotations can be performed by hand with the help of a straightedge, a compass, and a protractor.
To rotate point A about point P by an angle of 130^(∘) measured counterclockwise, follow these five steps.
The protractor is placed as illustrated above when the rotation is counterclockwise. If the rotation has to be done clockwise, the protractor needs to be placed as follows.
The intersection of the ray and the arc is the image A' after the give rotation.
Notice that this method of construction has also confirmed that PA is congruent to PA'.
Vincenzo and Zosia are two friends who love exploring the world of puzzles. Within the pages of a book discussing transformations, they find a circular disk with letters on it. They decide to call the disk a Cyrptawheel. The Cryptawheel has a movable triangle with one vertex fixed at the center of the circular disk. To reveal its secrets, the friends need to rotate the triangle.
The center of rotation is O and the angle of rotation is 180^(∘). Perform the rotation by rotating one point at a time. To rotate N, place the center of the protractor on O and align it with NO. Use the protractor to draw a ray that starts from O and makes a 180^(∘) angle with NO.
Then, mark a point N' on this ray so that ON' is the same length as ON. This is the image of N after the rotation. Since ON is the radius of the inner circle, N' should also be on that circle.
Repeat the same process for the vertex E to find E'. Since O is the center of rotation, O' will be in the same position as O.
Finally connect N', E', and O' to draw the image of NEO after the 180^(∘) rotation.
As shown, the image N' corresponds to P and E' corresponds to T. Therefore, the clue Vincenzo and Zosia is looking for is NEPT.
Notice that a 180^(∘) clockwise rotation and a 180^(∘) counterclockwise rotation produce the same image. Therefore, there is no need to specify direction when rotating a figure by 180^(∘).
In the coordinate plane, when a point is rotated counterclockwise around the origin at certain angles, its coordinates change in a specific way. This occurs when the angle of rotation is 90^(∘), 180^(∘), or 270^(∘). Try to figure these patterns out using the following applet.
| Counterclockwise Rotations Around the Origin | |
|---|---|
| Angle of Rotation | Rule |
| 90^(∘) | (x,y) → (- y,x) |
| 180^(∘) | (x,y) → (- x,- y) |
| 270^(∘) | (x,y) → (y,- x) |
The clue Vincenzo and Zosia found reminded them of the word Neptune.
Vincenzo had previously heard stories about this magical place. He had even heard about three ordinary students who had found a door into a mystical library. Could this be another doorway to that place? As they got closer, a puzzle appeared between the columns of the gate.
Graph the figure and its image after a 90^(∘) counterclockwise rotation about the origin on the same coordinate plane.
When a counterclockwise rotation is performed about the origin, the coordinates of the image can be written in relation to the coordinates of the preimage.
| Counterclockwise Rotations About the Origin | ||
|---|---|---|
| 90^(∘) Rotation | 180^(∘) Rotation | 270^(∘) Rotation |
|
ccc Preimage & & Image [0.5em] (x,y) & → & (- y,x) |
ccc Preimage & & Image [0.5em] (x,y) & → & (- x,- y) |
ccc Preimage & & Image [0.5em] (x,y) & → & (y,- x) |
Use the coordinate changes shown in the table that correspond to a 90^(∘) counterclockwise rotation about the origin to determine the coordinates of the image of each point. ccc Preimage & & Image [0.3em] (x,y) & → & (- y, x) [0.5em] [-0.5em] A(- 5,- 1) & → & A'(1,- 5) [0.5em] B(- 2,- 3) & → & B'(3,- 2) [0.5em] C(- 5,- 5) & → & C'(5,- 5) [0.5em] D(- 4,- 3) & → & D'(3,- 4) Now plot the image points and connect them. The final figure will be the image of the given figure after the rotation!
The gate swings open as the figure rotates into place. Zosia takes the first step through the gate, while Vincenzo hesitantly waits to see what happens. Use the sliders to see how Zosia's size changes as she passes through the gate and down the hall.
Feeling braver, Vincenzo steps through the gate as well. Inside, her and Zosia find an old notebook with a big red dot on one page. Zosia draws a figure on the page and watches as it changes size.
As they explore the magical realm, Vincenzo and Zosia come across Dilatius the Dimension Shifter, a wizard who can change the size of objects using dilations. They realize that the notebook they found belongs to the wizard and excitedly ask him to teach them about dilation. Dilatius thrilled to share his knowledge with them.
A dilation is a transformation that changes the size of a figure while keeping its shape the same. This transformation involves enlarging or reducing the figure by a certain length scale factor k from a fixed point O called the center of dilation. For example, the image of every point on a leaf lies on the ray that starts at the center of the dilation and passes through its preimage.
OA'=k * OA ⇔ k = OA'/OA
When a point is dilated using a scale factor of k and a center of dilation at the origin, the coordinates of its image are found by multiplying the coordinates of the preimage by k.
(x,y) → ( kx, ky)
The diagram shows how the image changes as the preimage and the scale factor change.
Dilatius is impressed by Vincenzo and Zosia's eagerness to learn. They seem to have picked up the dilation spell using the coordinate rule quickly, so he challenges them to dilate the following triangle.
Draw the image of the triangle after a dilation with center (0,0) and a scale factor of 3.
When the center of dilation is the origin, each coordinate of the preimage is multiplied by the scale factor k to find the coordinates of the image. ccc Preimage & & Image [0.5em] (x,y)& ⇒ & ( kx, ky) Find the coordinates of the vertices of △ A'B'C' after a dilation with a scale factor k= 3.
| Dilation With Scale Factor k=3 | ||
|---|---|---|
| Preimage | Multiply by k | Image |
| A(0,2) | ( 3* 0, 3 * 2 ) | A'(0,6) |
| B(3,1) | ( 3* 3, 3 * 1 ) | B'(9,3) |
| C(2,- 1) | ( 3* 2, 3 * (- 1) ) | C'(6,- 3) |
Finally, plot the image points and connect them with segments. The new triangle will be the image of the given figure after the dilation!
Notice that OA' is 3 times as long as OA since 3 is the scale factor. This also applies to other side lengths. OA' = 3 * OA OB' = 3 * OB OC' = 3 * OC
Dilatius teaches Vincenzo and Zosia to use reducio
to make things smaller and enlargio
to make them bigger. These phrases produce a reduction and an enlargement, respectively. He then quizzes them about the magic behind the drawings in his notebook.
The green square is a dilation of the blue square. Determine whether the dilation is an enlargement or a reduction and the scale factor of the dilation. rcc & Type of Dilation & Scale Factor [1em] A. & Reduction & 1/2 [1em] B. & Enlargement & 3/2 [1em] C. & Reduction & 2/3 [1em] D. & Enlargement & 3
In the given coordinate plane, it can be seen that the green square is smaller than the blue square. This means that the dilation is a reduction.
Next, remember that the scale factor is the ratio of the sides lengths of the image to the corresponding side lengths of the preimage. Scale Factor= Image Side Length/Preimage Side Length In the graph, AB is 9 units long and the corresponding side A'B' is 6 units long.
Substitute these values into the formula to find the scale factor. Scale Factor= 6/9 = 2/3 The scale factor is equal to 23. Therefore, the green square is a reduction of the blue square with a scale factor of 23. The answer is C.
The square ABCD has a side length of 9 units, while the square A'B'C'D' has a side length of 6 units. Therefore, the scale factor is 69, or 23.
Reflecting on their journey, Vincenzo and Zosia realized that both rotations and dilations preserve the original shape of an object. Consider, for example, a triangle. No matter how much it is rotated or dilated, its image is still a triangle.
On Paulina's treasure map, * marks the spot. She currently standing at point P.
The following transformations will lead Paulina to the treasure, but they are not in the correct order. I. & Reflect in they-axis II. & Rotate90^(∘) counterclockwise about the origin III. & Translate1 unit right and1 unit down IV. & Rotate180^(∘) about the origin Using each transformation exactly once, which of the following orders will guide Paulina to the treasure?
Let's take a look at the given map. It displays a green point representing Paulina's position and a red X indicating the location of the treasure on the coordinate plane.
We want to get to the treasure by applying each of the given transformations only once.
| Transformation | Rule | |
|---|---|---|
| I | Reflect in the y-axis | (x,y) → (- x, y) |
| II | Rotate 90^(∘) counterclockwise about the origin | (x,y) → (- y,x) |
| III | Translate 1 unit right and 1 unit down | (x,y) → (x+1,y-1) |
| IV | Rotate 180^(∘) about the origin | (x,y) → (- x,- y) |
We will proceed by trying the order in the options. Our starting point is (- 4,- 2). Let's start with the order in Option A.
The order in Option A led us to the treasure at (3,3). The answer is A. Using a similar table, we can verify that the remaining options do not lead to the treasure.
There are many ways to reach the treasure using these four transformations. Use the applet to apply the given transformations in any order. How many paths to the treasure can you find?