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Pearson Geometry Common Core, 2011

PG

Pearson Geometry Common Core, 2011 View details

Cumulative Standards Review

Exercise 2 Page 608

In a 30^(∘)-60^(∘)-90^(∘) triangle, the longer leg is sqrt(3) times the length of the shorter leg.

H

Practice makes perfect

Let x be the length of the longest leg.

In a 30^(∘)-60^(∘)-90^(∘) triangle, the longer leg is sqrt(3) times the length of the shorter leg. x=13* sqrt(3) We found that the measure of the longer leg is 13sqrt(3). Therefore, the answer is H.