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Pearson Geometry Common Core, 2011

PG

Pearson Geometry Common Core, 2011 View details

Cumulative Standards Review

Exercise 16 Page 486

Theorem 6.6 states that the diagonals of a parallelogram bisect each other.

7.5

Practice makes perfect

Knowing that DB=15 and ABCD is a parallelogram, we want to find the length of DE.

Theorem 6.6 states that the diagonals of a parallelogram bisect each other. Therefore, the following segments are congruent. AE ≅ EC and DE ≅ EB It means that their lengths are equal. AE = EC and DE = EB Since we know that DB=15 and DB=DE + EB, we can now calculate DE.

DB=DE+EB

EB= DE, DB= 15

15=DE+ DE

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Solve for DE

Add terms

15=2DE

.LHS /2.=.RHS /2.

7.5=DE

Rearrange equation

DE=7.5

Subchapter links

Exercises p.484-486