Sign In
The top row contains two cans. Then, each row has one more can than the previous.
Use the explicit formula from Part A. For the summation notation the lower and upper limits are 1 and 10, respectively.
Use the formula obtained in Part A.
Use the formula for the sum of a finite arithmetic series.
a_n=n+1
∑_(n=1)^9(n+1)
18 cans
Could the triangle have 110 cans? No.
Could the triangle have 140 cans? No.
Note that the top row contains 2 cans. Moreover, each row contains 1 more can than the previous row. Therefore, the number of cans in each row form an arithmetic sequence. Let's recall the explicit rule for this type of sequence.
a= 2, d= 1
Identity Property of Multiplication
Remove parentheses
Subtract term
The explicit formula for the sequence of the number of cans is a_n=n+1.
The related arithmetic series is the sum of the terms of the sequence from Part A. Since any triangle formed by cans has a first row, the lower limit of the summation is 1.
∑_(n= 1)^?(n+1)
The triangle has 9 rows. This is the upper limit for the summation. ∑_(n=1)^9(n+1)
In Part A, we obtained that the number of cans in the nth row is given by the formula a_n=n+1. Therefore, to find the number of cans in the 17th row we will substitute 17 for n in this formula and simplify.
There are 18 cans in the 17th row.
Let's start by considering the formula for the sum of a finite arithmetic series.
S_n=n/2(a_1 + a_n)
Here, n is the number of terms of the series and a_1 and a_n are the first and last terms, respectively. We know that the first term of our series is a_1= 2. Moreover, from Part A, we know that a_n=n+1.
S_n= 110
LHS * 2=RHS* 2
Add terms
Distribute n
LHS-220=RHS-220
Commutative Property of Addition
Rearrange equation
Note that we have a quadratic equation with coefficients a= 1, b= 3, and c= - 220. To solve it we will use the Quadratic Formula.
Substitute values
Calculate power
Identity Property of Multiplication
a(- b)=- a * b
a-(- b)=a+b
Use a calculator
State solutions
(I), (II): Add and subtract terms
(I), (II): Calculate quotient
Be aware that n represents the nth row in the triangle. Therefore, a value of n that is not a natural number does not make sense. We supposed the triangle had 110 cans, and arrived to the conclusion that there are either 13.4 or - 16.4 rows. None of these numbers make sense, so the triangle cannot have 110 cans. By the same method let's see if the triangle can have 140 cans.
| Cans | Substitute | Simplify | Value of n |
|---|---|---|---|
| 110 | 110 = n/2(2+n+1) | n^2+3n-220=0 | n≈ 13.4 or n≈ - 16.4 |
| 140 | 140 = n/2(2+n+1) | n^2+3n-280=0 | n≈ 15.3 or n≈ - 18.3 |
Since the triangle cannot have 15.3 nor - 18.3 rows, we conclude that it cannot have 140 cans.