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Use the formula for the sum of a finite arithmetic series.
75
We are given a finite series in summation notation and want to find its sum. ∑^(10)_(n=5) (20-n) Since the formula is a linear function of n, we know that the series is arithmetic. To calculate the sum, we need to find the first and last terms. Let's substitute 1 and 10 for n in 20-n.
| a_n=20-n | |
|---|---|
| a_1=20- 1 | a_(10)=20- 10 |
| a_1=19 | a_(10)=10 |
a_1= 19, n= 10
a_(10)= 10
The sum of the first ten terms of the series is 145. However, if we pay close attention to the given summation notation, we can see that our series starts at n=5. This means that we only want to calculate the sum from n=5 to n=10. ∑^(10)_(n=5) (20-n) Since we already found the sum of all the terms, we will now calculate the sum of the first four terms and find the difference. To find the sum of the first four terms, we need to calculate the fourth term, a_4, and then we can once again use the formula for the sum of an arithmetic series.
Now, let's substitute n=4, a_1=19, and a_n=16 into the formula.
Finally, we can find the sum of the terms indicated in the given summation notation. ∑^(10)_(n=5) (20-n) = 145-70=75