Pearson Algebra 2 Common Core, 2011
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Pearson Algebra 2 Common Core, 2011 View details
4. Arithmetic Series
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Exercise 26 Page 591

Use the formula for the sum of a finite arithmetic series.

75

Practice makes perfect

We are given a finite series in summation notation and want to find its sum. ∑^(10)_(n=5) (20-n) Since the formula is a linear function of n, we know that the series is arithmetic. To calculate the sum, we need to find the first and last terms. Let's substitute 1 and 10 for n in 20-n.

a_n=20-n
a_1=20- 1 a_(10)=20- 10
a_1=19 a_(10)=10
Now that we know a_1=19 and a_(10)=10, we will calculate the sum of the series substituting a_1= 19, n= 10, and a_(10)= 10 in the formula for the sum of a finite arithmetic series.
S_n=n/2(a_1+a_n)
S_(10)=10/2( 19+a_(10))
S_(10)=10/2(19+ 10)
Evaluate right-hand side
S_(10)=5(19+10)
S_(10)=5(29)
S_(10)=145
The sum of the first ten terms of the series is 145. However, if we pay close attention to the given summation notation, we can see that our series starts at n=5. This means that we only want to calculate the sum from n=5 to n=10. ∑^(10)_(n=5) (20-n) Since we already found the sum of all the terms, we will now calculate the sum of the first four terms and find the difference. To find the sum of the first four terms, we need to calculate the fourth term, a_4, and then we can once again use the formula for the sum of an arithmetic series.
a_n=20-n
a_()deepskyblue4=20-4
a_4=16
Now, let's substitute n=4, a_1=19, and a_n=16 into the formula.
S_n=n/2(a_1+a_n)
S_4=4/2( 19+16)
Evaluate right-hand side
S_4=2(19+16)
S_4=2(35)
S_4=70
Finally, we can find the sum of the terms indicated in the given summation notation. ∑^(10)_(n=5) (20-n) = 145-70=75