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Use the given the zeros to write a rational function. Then, check if the ratio of the leading coefficients is 1.
If the horizontal asymptote is y=0, what can you say about the degrees of the numerator and denominator?
If the horizontal asymptote is y=3, what can you say about the degrees of the numerator and denominator?
Example Function:
f(x)=x^2-7x+12/x^2+2x-3
Example Function:
f(x)=x+4/x^2-3x
Example Function:
f(x)=3(x+1)^2/x^2-4
We want to write a rational function in the following form.
f(x)=P(x)/Q(x)
| Q(x) | P(x) | |
|---|---|---|
| Zeros | Vertical Asymptotes x=1 and x=- 3 |
x=3 and x=4 |
| Factors | (x-1) and (x+3) | (x-3) and (x-4) |
We have found the factors. Since the horizontal asymptote is y=1, the ratio of the leading coefficients should be 1. Let's write the function. f(x)=(x-3)(x-4)/(x-1)(x+3) ⇕ f(x)=x^2-7x+12/x^2+2x-3 Notice that the ratio of the leading coefficients is 1. Please note that we can find infinitely many functions to this exercise. Here we are only showing one possibility.
We want to write a rational function in the following form.
f(x)=P(x)/Q(x)
| Q(x) | P(x) | |
|---|---|---|
| Zeros | Vertical Asymptotes x=0 and x=3 |
x=- 4 |
| Factors | x and (x-3) | (x+4) |
We have found the factors. Since the horizontal asymptote is y=0, the highest degree of the numerator is less than the highest degree of the denominator. Let's write the function. f(x)=x+4/x(x-3) ⇕ f(x)=x+4/x^2-3x Notice that the degree of the numerator, 1, is less than the degree of the denominator, 2. Please note that we can find infinitely many functions to this exercise. Here we are only showing one possibility.
We want to write a rational function in the following form.
f(x)=P(x)/Q(x)
| Q(x) | P(x) | |
|---|---|---|
| Zeros | Vertical Asymptotes x=- 2 and x=2 |
only one zero at x=- 1 |
| Factors | (x+2) and (x-2) | (x+1) |
We have found the factors. Since the horizontal asymptote is at y=3, other than zero, the highest degree of the numerator and the denominator are equal. Therefore, we should use (x+1) two times as a factor in the numerator. Moreover, the ratio of leading coefficient should be 3. Let's write the function. f(x)=3(x+1)(x+1)/(x+2)(x-2) ⇕ f(x)=3(x+1)^2/x^2-4 Notice that the ratio of the leading coefficients is 3. Please note that we can find infinitely many functions to this exercise. Here we are only showing one possibility.
| Function | If | Horizontal Asymptote at |
|---|---|---|
| f(x)=P(x)/Q(x) | deg(P(x)) > deg(Q(x)) | No horizontal asymptote |
| deg(P(x)) = deg(Q(x)) | y=a/b | |
| deg(P(x)) < deg(Q(x)) | y=0 |
The table below shows how to find any vertical asymptotes.
| Function | If | Vertical Asymptote at |
|---|---|---|
| f(x)=P(x)/Q(x) | P(x) and Q(x) have no common zero | each zero of Q(x) |
| P(x)=(x-a)^m * p(x) and Q(x)=(x-a)^n * q(x) for some p(x) and q(x), and m< n |
each zero of Q(x) and x=a |