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Division by zero is not defined. This means that the denominator cannot be zero.
To graph the given rational function, we will find its domain, asymptotes, and intercepts. Then, we will find points using a table of values. Finally, we will plot and connect those points.
This means that x=0, x=-2, and x=2 are not included in the domain. Domain All real numbers except x=0, x=-2, and x=2
Asymptotes can be vertical or horizontal lines.
holein the graph at x=0. Since the factors x+2, and x-2 are still in the denominator, we have a vertical asymptotes at x=-2 and x=2.
To find the horizontal asymptotes, we can use a set of rules. To properly use these rules, in the following table m and n must be the highest degree of the numerator and denominator.
| y=ax^m/bx^n | Asymptote |
|---|---|
| m | y=0 |
| m>n | none |
| m=n | y=a/b |
Now, consider the function one more time. Let's look at the degrees of the numerator and denominator for our function. y=4x^1/x^3-4 We can see that the degree of the denominator is higher than the degree of the numerator. Therefore, the line y=0 is a horizontal asymptote.
The intercepts of the function are the points at which the graph intersects the axes.
Since x=0 is not included in the domain, there is no y-intercept.
Let's make a table of values to graph the given function. Make sure to only use values included in the domain of the function.
| x | 4x/x^3-4x | y=4x/x^3-4x |
|---|---|---|
| -4 | 4( - 4)/( - 4)^3-4(-4) | ≈ 0.333 |
| - 3 | 4( - 3)/( - 3)^3-4( -3) | 0.8 |
| - 1 | 4( - 1)/( - 1)^3-4(-1) | ≈ - 1.333 |
| -0.5 | 4( - 0.5)/( - 0.5)^3-4(-0.5) | ≈ - 1.067 |
| 0.5 | 4( 0.5)/( 0.5)^3-4( 0.5) | ≈ - 1.067 |
| 1 | 4( 1)/1^3-4( 1) | ≈ - 1.333 |
| 3 | 4( 3)/3^2-4( 3) | 0.8 |
| 4 | 4( 4)/4^3-4( 4) | ≈ 0.333 |
Finally, let's plot and connect the points. Do not forget to draw the asymptotes and to plot the intercepts and holes, if any.