Pearson Algebra 2 Common Core, 2011
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Pearson Algebra 2 Common Core, 2011 View details
1. Inverse Variation
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Exercise 19 Page 503

Practice makes perfect
a The function that describes the amount of sales given the number of sold muffins will be a direct variation function. This is because the recorded sales only depends on the number of sold muffins. Therefore to get s we have to multiply m with some coefficient k.
Direct Variation s = km [-1em] Constant of Variation: kTo find k, we need to choose one ordered pair from the table of values and solve for k. We can, for example, choose the fourth value (20,50).
s = km
50 = k( 20)
50 = 20k
2.5 = k
k= 2.5
Now we can complete the equation. s = 2.5m
b We can use the function we created from Part A to find the minimum number of muffins that must be sold. Recall that the phrase at least is the same thing as saying greater than or equal to. Since s represents sales, we want s to be greater than or equal to 250.
s ≥ 250 By substituting s=2.5m, we can then solve for m by performing inverse operations.
s ≥ 250
2.5m ≥ 250
m ≥ 100
When the number of sold muffins is greater than or equal to 100, we make at least $250 profit.