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LHS-36
Write as a power
a^2-b^2=(a+b)(a-b)
Since the product of the binomials obtained should be negative, as stated by the inequality symbol (x+6)(x-6) <0, the quantities represented by the binomials should have different signs. Then, we have two options.
| Option 1 | Option 2 | |
|---|---|---|
| Factors' Signs | x+6<0 and x-6>0 | x+6>0 and x-6<0 |
| Simplified Form | x< - 6 and x>6 | x>- 6 and x<6 |
| Solution Set | no solution | - 6 |
The solution set for the inequality is - 6
Since the product of the binomials obtained should be positive, as stated by the inequality symbol (x+3)(x-3) >0, the quantities represented by the binomials should have the same signs. We have the two options.
| Option 1 | Option 2 | |
|---|---|---|
| Factors' Signs | x+3>0 and x-3>0 | x+3<0 and x-3<0 |
| Simplified Form | x> - 3 and x>3 | x< - 3 and x<3 |
| Solution Set | x>3 | x<- 3 |
The solution set for the inequality is then x< - 3 or x>3. To graph the solution set we need to use two open points at -3 and 3, as the inequality symbols do not include the boundary values. Then, we shade to the left of -3 and to the right of 3.
| Factors of - 18 | Sum |
|---|---|
| 1,- 18 | 1-8 = - 7 * |
| 2,- 9 | 2 - 9 = -7 * |
| 3,- 6 | 3-6 = - 3 ✓ |
With this in mind, we can factor our expression. x^2-3x-18 >0 ⇕ (x + 3)(x - 6) >0 Since the product of the binomials obtained should be positive, as stated by the inequality symbol (x+3)(x-6) >0, the quantities represented by the binomials should have the same signs. Then, we have two two options.
| Option 1 | Option 2 | |
|---|---|---|
| Factors' Signs | x+3>0 and x-6>0 | x+3<0 and x-6<0 |
| Simplified Form | x> - 3 and x>6 | x< - 3 and x<6 |
| Solution Set | x>6 | x<- 3 |
The solution set for the inequality is then x< - 3 or x>6. To graph the solution set we need to use two open points at -3 and 6, as the inequality symbols do not include the boundary values. Then, we shade to the left of -3 and to the right of 6.