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Graph each inequality. The solution will be the intersection, or overlap, of the shaded regions.
Example Solution: (0,3)
Graphing a single inequality involves two main steps.
The system's solution set will be the intersection of the shaded regions in the graphs of (I) and (II).
We can tell a lot of information about the boundary lines from the inequalities given in the system.
Let's find each of these key pieces of information for the inequalities in the system.
Information | Inequality (I) | Inequality (II) |
---|---|---|
Given Inequality | x+y>2 | 3x+2y≤6 |
Boundary Line Equation | x+y=2 | 3x+2y=6 |
Solid or Dashed? | > ⇒ Dashed | ≤ ⇒ Solid |
y= mx+ b | y= -1x+ 2 | y= -3/2x+ 3 |
Great! With all of this information, we can plot the boundary lines.
We need to determine on which side of the plane the solution set of each inequality lies. To do that, we will need a test point that does not lie on either boundary line.
It looks like the point ( 0, 0) would be a good test point. We will substitute this point for x and y in the given inequalities and simplify. If the substitution creates a true statement, we shade the same region as the test point. Otherwise, we shade the opposite region.
Information | Inequality (I) | Inequality (II) |
---|---|---|
Given Inequality | x+y>2 | 3x+2y ≤ 6 |
Substitute (0,0) | 0+ 0? >2 | 3( 0)+2( 0) ? ≤ 6 |
Simplify | 0≯ 2 | 0≤6 |
Shaded Region | opposite | same |
For Inequality (I) we will shade the region opposite our test point, or above the boundary line. For Inequality (II), however, we will shade the region containing the test point, or below the boundary line.
To identify a solution to this system of inequalities, we can choose any point that lies within the overlapping shaded region. Above we have selected the lattice point (0,3). Note that this is only one of infinitely many possible coordinate pairs that are solutions to the system.