body{margin:0;} noscript{z-index: 10000; position: fixed; display: block; height: 100%; width: 100%; background: #fff;} noscript .fa{font-size: 40px; display:block; color: #daa520;} noscript div{margin-top: 6%; padding-left: 20px; padding-right: 20px; text-align: center;} ! You must have JavaScript enabled to use this site.

Pearson Algebra 2 Common Core, 2011

PA

Pearson Algebra 2 Common Core, 2011 View details

2. Solving Trigonometric Equations Using Inverses

Continue to next subchapter

Exercise 32 Page 916

Start by rewriting the equation so that all the terms are on one side. Next, factor the equation and use the Zero Product Property. Then, draw the unit circle on the coordinate plane.

$0$ radians and $π$ radians

Practice makes perfect

To solve the given equation, we will first rewrite it so that all the terms are on one side. Next, we will factor the equation and use the Zero Product Property to solve for $sin θ$ and $cos θ .$ Then we will use the unit circle to find the exact values of $θ$ that satisfy the equation.

Solving the Equation for $sin θ$ and $cos θ$

Let's start by rewriting the equation so that all of the terms are on the left-hand side.

sin θ = - sin θ cos θ

$LHS + sin θ cos θ = RHS + sin θ cos θ$

sin θ + sin θ cos θ = 0

Now we can factor the expression on the left-hand side.

sin θ + sin θ cos θ = 0

Factor out $sin θ$

sin θ (1 + cos θ) = 0

A shortcut to better grades

Download the app and create a free account to view full content

Subchapter links

Lesson Check p.915

Practice and Problem-Solving Exercises p.916-918

Standardized Test Prep p.918

Mixed Review p.918