Pearson Algebra 2 Common Core, 2011
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Pearson Algebra 2 Common Core, 2011 View details
3. Right Triangles and Trigonometric Ratios
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Exercise 29 Page 925

In a right triangle, the tangent of an acute angle is defined as the ratio of the length of the opposite side to the length of the adjacent side.

Triangle:

Trigonometric Ratios: sin θ=24/25, cos θ=7/25, csc θ=25/24, sec θ=25/7, cot θ=7/24

Practice makes perfect

Given that tan θ= 247, we want to sketch a right triangle with θ as the measure of one acute angle. Then, we will find the other five trigonometric ratios of θ. Let's do these things one at a time.

Drawing the Triangle

In a right triangle, the tangent of an acute angle is defined as the ratio of the length of the opposite side to the length of the adjacent side. tan θ =24/7 ⇔ tan θ = opposite/adjacent

Therefore, we know that the length of the opposite side to θ is 24 and that the length of the adjacent side to θ is 7.

We can find the length of the hypotenuse by substituting a= 7 and b= 24 into the Pythagorean Theorem.
a^2+b^2=c^2
7^2+ 24^2=c^2
Solve for c
49+576=c^2
625=c^2
sqrt(625)=c
25=c
c= 25
Note that when solving the equation we only considered the principal root. This is because c represents a side length and therefore must be a positive number. We can now draw the right triangle and label its three sides.

Finding Trigonometric Ratios

Having the three sides of the right triangle allows us to find the five remaining trigonometric ratios.

Function Substitute
sin θ=opp/hyp sin θ=24/25
cos θ=adj/hyp cos θ=7/25
sec θ=hyp/adj sec θ=25/7
csc θ=hyp/opp csc θ=25/24
cot θ=adj/opp cot θ=7/24