Pearson Algebra 2 Common Core, 2011
PA
Pearson Algebra 2 Common Core, 2011 View details
3. Right Triangles and Trigonometric Ratios
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Exercise 25 Page 924

Practice makes perfect
a

An observer that is on the ground at point A watches a rocket ascend from the point B. The observer is 1200 feet from launch point B.

As the rocket rises, the distance d from the observer to the rocket increases. We want to express m ∠ A in terms of d. To do so, we can use the trigonometric ratio for cosine. cos θ = Adjacent/Hypotenuse In our case, the length of the adjacent leg is 1200 and the hypotenuse is the distance between the observer and the rocket. cos θ = Adjacent/Hypotenuse ⇓ cos A = 1200/d We will find an expression for m∠ A by applying the inverse cosine in each side of this equation. cos A = 1200/d ⇓ m∠ A = cos^(- 1) ( 1200/d )

b

We want to find the value of m∠ A when the distance is 1500 feet. To do so, we will use the expression found in Part A.

m∠ A = cos^(- 1) ( 1200/d ) We will substitute 1500 for d in this formula and then we will evaluate it to find the value of m∠ A. Let's do it!

m∠ A = cos^(- 1) 1200/d
m∠ A = cos^(- 1) 1200/1500
m∠ A = 36.869897 ...
m∠ A ≈ 37^(∘)

c

Finally, we will calculate m∠ A by substituting d as 2000 feet into the formula found in Part A.

m∠ A = cos^(- 1) ( 1200/d ) ⇓ m∠ A = cos^(- 1) ( 1200/2000 ) Now, we will evaluate this expression to get the value of m∠ A. Let's do it!

m∠ A = cos^(- 1) 1200/2000
m∠ A = 53.130102 ...
m∠ A ≈ 53 ^(∘)