Exercise 20 Page 924

First, let's draw the measurements from the exercise on a right triangle to visualize the given information.

We will find the missing measures one at a time. In this case, this means that we want to find m ∠ A, m ∠ B, and c.

Angle Measures

We can find m ∠ B using a tangent ratio. The tangent of ∠ B is the ratio of the length of the leg opposite ∠ B to the length of the leg adjacent ∠ B. tan B=Opposite/Adjacent ⇒ tan B =6/5 By the definition of the inverse tangent, the inverse tangent of 65 is the measure of ∠ B. To find it, we have to use a calculator.

m∠ B=tan ^(-1) 6/5

UseCalc

Use a calculator

m∠ B = 50.194428... ^(∘)

RoundDec

Round to 1 decimal place(s)

m∠ B ≈ 50.2 ^(∘)

To find m∠ A, recall that the acute angles of a right triangle are complementary. Therefore, m ∠ A and m ∠ B add up to 90^(∘). m ∠ A + m ∠ B = 90^(∘) Now, we can substitute the approximated measure of ∠ B in our equation and find the measure of ∠ A. m ∠ A + 50.2 ^(∘) ≈ 90^(∘) ⇔ m ∠ A ≈ 39.8^(∘)

Side Lengths

Finally, we can find the measure of c. To do it, we can use the Pythagorean Theorem. a^2 + b^2 = c^2 Let's substitute the known lengths, a = 5 and b= 6, into this equation to find c.

a^2+b^2=c^2

SubstituteII

a= 5, b= 6

5^2 + 6^2= c^2

▼

Solve for c

CalcPow

Calculate power

25+36=c^2

AddTerms

Add terms

61=c^2