Pearson Algebra 2 Common Core, 2011
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Pearson Algebra 2 Common Core, 2011 View details
2. Angles and the Unit Circle
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Exercise 2 Page 840

Draw a right triangle with one of its legs on the x-axis and label its sides according to the coordinates of the given point.

240^(∘)

Practice makes perfect

We want to find the measure of the angle in standard position. To do so, we will draw a right triangle with one of its legs on the x-axis. We will also label its sides according the coordinates of the given point.

The length of the longer leg of the triangle is sqrt(3) times the length of the shorter leg. This means that we have a 30^(∘)-60^(∘)-90^(∘) triangle. In this type of triangle, the measure of the angle opposite the shorter leg is 30^(∘). Next, to calculate the required angle θ, we will subtract the obtained value from 270^(∘), which is the measure of three quarters of a circle. 270^(∘) -30^(∘) = 240^(∘) Finally, let's see the angle on the graph.

Alternative Solution

Using Trigonometry

The angle measure can also be found using right triangle trigonometry. Consider the right triangle we drew at the beginning of the solution.

In a right triangle, the tangent of an acute angle is equal to the ratio of the length of the opposite leg to the length of the adjacent leg. tan θ = Opposite leg/Adjacent leg In our diagram, we can see that the length of the opposite leg is 12, and the length of the adjacent leg is sqrt(3)2. Let's substitute these values into the above formula and solve for θ.
tan θ = opp/adj
tan θ = 12/sqrt(3)2
tan θ = 1/sqrt(3)
To find the value of θ we will use the inverse of the tangent function, tan^(- 1). tan θ =1/sqrt(3) ⇔ θ =tan^(- 1) 1/sqrt(3) Then, we will need to use a calculator. θ =tan^(- 1) 1/sqrt(3) ⇒ θ=30^(∘) As we can see, the angle θ is 30^(∘). To obtain the measure of the given angle, we need to subtract this value from 270^(∘), as we did in the solution. 270^(∘)-30^(∘) = 240^(∘)