body{margin:0;} noscript{z-index: 10000; position: fixed; display: block; height: 100%; width: 100%; background: #fff;} noscript .fa{font-size: 40px; display:block; color: #daa520;} noscript div{margin-top: 6%; padding-left: 20px; padding-right: 20px; text-align: center;} ! You must have JavaScript enabled to use this site.

Pearson Algebra 2 Common Core, 2011

PA

Pearson Algebra 2 Common Core, 2011 View details

Cumulative Standards Review

Exercise 14 Page 759

We will use the Quadratic Formula to solve the given quadratic equation.

a x^{2} + b x + c = 0 ⇕ x = \frac{- b \pm b ^{2} - 4 a c}{2 a}

We want to know the value of

x

when

y

is equal to

0 .

Let's start by substituting

0

for

y

and rewriting the equation so all of the terms are on the left-hand side.

A shortcut to better grades

Download the app and create a free account to view full content

Subchapter links

Exercises p.758-760

Vocabulary Review