Pearson Algebra 1 Common Core, 2011
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Pearson Algebra 1 Common Core, 2011 View details
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Exercise 20 Page 607

Use the graph to make a table of points. Find how the y-values change with each x-value.

Type of Function: Exponential
Equation: y=40( 12)^x

Practice makes perfect

Identify the Type of Function

First let's identify if the graph is linear, quadratic, or exponential. We will make a table of points from the graph.

x y
0 40
1 20
2 10
3 5

Now to determine what kind of function this is, let's look at how the y-value changes each time.

We can see that each y-value is always being halved. Since the change between each y-value has a common ratio, we know that the function is exponential.

Alternatively, we can see that this function is exponential by looking at the graph. The graph is not a line, so the function is not linear. Similarly, the graph does not appear to be a parabola, so the function is not quadratic.

Writing an Equation

Now we will write an equation for this exponential function. Let's use the general model for exponential functions. y=ab^x In the equation a is the initial value. That is, it is the y-value when x=0. We can see from our table and graph that when x=0, y=40. y=40b^x Now, let's find the b-value, which represents the decay factor. In our scenario, we can see that each y-value gets cut in half. This tells us that the decay factor is 12. y=40(1/2)^x We now have an equation that models the data.