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Start by identifying the values of a, b, and c.
Graph:
To draw the graph of the related function written in standard form, we must start by identifying the values of a, b, and c.
f(x)=- x^2-2 ⇕ f(x)=- 1x^2+ x+(- 2)
We can see that a=- 1, b= , and c=- 2. Now, we will follow three steps to graph the function.
The axis of symmetry is a vertical line with equation x=- b2a. Since we already know the values of a and b, we can substitute them into the formula.
The axis of symmetry of the parabola is the vertical line with equation x=0.
Next, we will make a table of values using x values around the axis of symmetry x=0.
| x | - x^2-2 | y |
|---|---|---|
| - 2 | - ( - 2)^2-2 | - 6 |
| - 1 | - ( - 1)^2-2 | - 3 |
| 0 | - 0^2-2 | - 2 |
| 1 | - 1^2-2 | - 3 |
| 2 | - 2^2-2 | - 6 |
We can finally draw the graph of the function. Since a=- 1, which is negative, the parabola will open downwards. Let's connect the points with a smooth curve.