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What do b and c in x^2+bx+c stand for?
(x+4)(x+3)
To factor a trinomial with a leading coefficient of 1, think of the process as multiplying two binomials in reverse. Let's start by taking a look at the constant term.
x^2+7x+ 12
In this case, we have 12. This is a positive number, so for the product of the constant terms in the factors to be positive, these constants must have the same sign (both positive or both negative).
| Factor Constants | Product of Constants |
|---|---|
| 1 and 12 | 12 |
| -1 and -12 | 12 |
| 2 and 6 | 12 |
| -2 and -6 | 12 |
| 3 and 4 | 12 |
| -3 and -4 | 12 |
Next, let's consider the coefficient of the linear term. x^2+ 7x+ 12 For this term, we need the sum of the factors that produced the constant term to equal the coefficient of the linear term, 7.
| Factors | Sum of Factors |
|---|---|
| 1 and 12 | 13 |
| -1 and -12 | -13 |
| 2 and 6 | 8 |
| -2 and -6 | -8 |
| 3 and 4 | 7 |
| -3 and -4 | -7 |
We found the factors whose product is 12 and whose sum is 7. x^2+ 7x+ 12 ⇔ (x+4)(x+3)
Distribute (x+4)
Distribute x
Distribute 3
Add terms
After applying the Distributive Property and simplifying, the result is the same as the given expression. Therefore, we can be sure our solution is correct!