Pearson Algebra 1 Common Core, 2011
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Pearson Algebra 1 Common Core, 2011 View details
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Exercise 24 Page 415

Substitute - 2, 0, and 3.5 for x.

Range : {- 11, - 1, 16.5}

Practice makes perfect
We can find the range of the function on the given domain using substitution. By substituting the values into the function, we will have the corresponding values in the range. Domain : {-2, 0 , 3.5 }This means that we should substitute -2, 0, and 3.5 for x in the given function and then evaluate. Let's start with - 2.
y=5x-1
y=5( - 2)-1
y=- 10 - 1
y=-11
Now, let's do the same thing for the rest of the values.
x Evaluation y
- 2 5( - 2)-1 - 11
0 5( 0)-1 - 1
3.5 5( 3.5)-1 16.5

For the domain {-2, 0, 3.5}, the range of the function is {- 11, - 1, 16.5}.