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Pearson Algebra 1 Common Core, 2011
PA
Pearson Algebra 1 Common Core, 2011 View details
Chapter Review
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Exercise 66 Page 477

Substitute 1, 2, and 3 for x.

6, 12, 24

Practice makes perfect

We are given a function, and asked to evaluate it for the given domain. Domain: {1, 2, 3 }This means that we should substitute 1, 2, and 3 for x in the given function and then evaluate. Let's start with 1.

f(x)=3 * 2^x
Substitute

x= 1

f( 1)=3 * 2^1
ExponentOne

a^1=a

f(1)=3 * 2
Multiply

Multiply

f(1)=6

Now, let's do the same thing for the rest of the values.

x 3 * 2^x f(x)=3 * 2^x
1 3 * 2^1 6
2 3 * 2^2 12
3 3 * 2^3 24

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arrow_right Exercises p.474-478
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Exercises 7 (Page 475)
Exercises 8 (Page 475)
Exercises 9 (Page 475)
Exercises 10 (Page 475)
Exercises 11 (Page 475)
Exercises 12 (Page 475)
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Exercises 46 (Page 476)
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Exercises 63 (Page 477)
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