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Pearson Algebra 1 Common Core, 2011
PA
Pearson Algebra 1 Common Core, 2011 View details
Chapter Review
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Exercise 65 Page 477

Substitute 1, 2, and 3 for x.

20, 10, 5

Practice makes perfect

We are given a function, and asked to evaluate it for the given domain. Domain: {1, 2, 3 }This means that we should substitute 1, 2, and 3 for x in the given function and then evaluate. Let's start with 1.

y=40(1/2)^x
Substitute

x= 1

y=40(1/2)^1
ExponentOne

a^1=a

y=40* 1/2
MoveLeftFacToNumOne

a* 1/b= a/b

y=40/2
CalcQuot

Calculate quotient

y=20

Now, let's do the same thing for the rest of the values.

x 40(1/2)^x y=40(1/2)^x
1 40(1/2)^1 20
2 40(1/2)^2 10
3 40(1/2)^3 5

Subchapter links expand_more
arrow_right Exercises p.474-478
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Exercises 7 (Page 475)
Exercises 8 (Page 475)
Exercises 9 (Page 475)
Exercises 10 (Page 475)
Exercises 11 (Page 475)
Exercises 12 (Page 475)
Exercises 13 (Page 475)
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Exercises 46 (Page 476)
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Exercises 63 (Page 477)
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Exercises 71 (Page 477)
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Exercises 82 (Page 478)
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