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Pearson Algebra 1 Common Core, 2011
PA
Pearson Algebra 1 Common Core, 2011 View details
Chapter Review
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Exercise 64 Page 477

Substitute 1, 2, and 3 for x.

0.01, 0.0001, 0.000001

Practice makes perfect

We are given a function, and asked to evaluate it for the given domain. Domain: {1, 2, 3 }This means that we should substitute 1, 2, and 3 for x in the given function and then evaluate. Let's start with 1.

y=0.01^x
Substitute

x= 1

y=0.01^1
ExponentOne

a^1=a

y=0.01

Now, let's do the same thing for the rest of the values.

x 0.01^x y=0.01^x
1 0.01^1 0.01
2 0.01^2 0.0001
3 0.01^3 0.000001

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Exercises 7 (Page 475)
Exercises 8 (Page 475)
Exercises 9 (Page 475)
Exercises 10 (Page 475)
Exercises 11 (Page 475)
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Exercises 46 (Page 476)
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Exercises 63 (Page 477)
Exercises 64 (Page 477)
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