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Pearson Algebra 1 Common Core, 2011

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Pearson Algebra 1 Common Core, 2011 View details

3. Solving Systems Using Elimination

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Exercise 46 Page 384

You'll need to substitute 0 for x and solve.

y-intercept: 3

Practice makes perfect

To determine the y-intercept for the given equation, we will need to substitute 0 for x and solve. Think of the point where the graph of an equation crosses the y-axis. The x-value of the ( x,y) coordinate pair at the y-intercept is 0, and the y-value is the y-intercept. To find the y-intercept of the equation, 2x+5y=15 we should substitute 0 for x and solve for y.

2x+5y=15

x= 0

2( 0)+5y=15

Zero Property of Multiplication

5y=15

.LHS /5.=.RHS /5.

y=3

A y-intercept of 3 means that the graph passes through the y-axis at the point (0,3).

Subchapter links

Lesson Check p.381

Practice and Problem-Solving Exercises p.382-384

Standardized Test Prep p.384

Mixed Review p.384