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Recall the multiplication laws of real numbers.
Example Solution: y = (- 1)^x
This is because multiplying two negative numbers gives us a positive result, and the product of a positive and a negative number gives us a negative number once again. We can use this for our function. In the example shown below, we can see that we will obtain this by using a power where the base is a negative number. rcccc (-2)^2 &=& 4 (-2)^3 &=& - 8 (-2)^4 &=& 16 For simplicity, we can use - 1 as the base. If we want the exponent to be changing, we can set it as the independent variable. Let's try with the function y = (- 1)^x.
x | (- 1)^x | y |
---|---|---|
1 | (- 1)^1 | - 1 |
2 | (- 1)^2 | 1 |
3 | (- 1)^3 | - 1 |
4 | (- 1)^4 | 1 |
Looking at the last column of the table, we can see that we found the behavior we wanted. The function y = (- 1)^x is negative for x=1, positive for x=2, negative for x=3, and positive at x=4, as required. Note that there are infinitely many solutions that satisfy the condition. This is just one of them.