Pearson Algebra 1 Common Core, 2011
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Pearson Algebra 1 Common Core, 2011 View details
3. Patterns and Nonlinear Functions
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Exercise 18 Page 250

Recall the multiplication laws of real numbers.

Example Solution: y = (- 1)^x

Practice makes perfect
We want to find a rule for a nonlinear function such that y is negative for x=1, positive for x=2, negative again for x=3, positive at x=4, and so on. Note that we can obtain this behavior when multiplying a series of negative numbers. - 2 (-2) &= 4 -2 (-2) (-2) &= - 8 -2 (-2) (-2) (-2) &= 16

This is because multiplying two negative numbers gives us a positive result, and the product of a positive and a negative number gives us a negative number once again. We can use this for our function. In the example shown below, we can see that we will obtain this by using a power where the base is a negative number. rcccc (-2)^2 &=& 4 (-2)^3 &=& - 8 (-2)^4 &=& 16 For simplicity, we can use - 1 as the base. If we want the exponent to be changing, we can set it as the independent variable. Let's try with the function y = (- 1)^x.

x (- 1)^x y
1 (- 1)^1 - 1
2 (- 1)^2 1
3 (- 1)^3 - 1
4 (- 1)^4 1

Looking at the last column of the table, we can see that we found the behavior we wanted. The function y = (- 1)^x is negative for x=1, positive for x=2, negative for x=3, and positive at x=4, as required. Note that there are infinitely many solutions that satisfy the condition. This is just one of them.