Pearson Algebra 1 Common Core, 2011
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Pearson Algebra 1 Common Core, 2011 View details
Mid-Chapter Quiz
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Exercise 5 Page 252

Which variable can you change? Can you choose how many tricks a dog will do? Can you choose how many dog biscuits left?

Independent Variable: Number of tricks
Dependent Variable: Dog biscuits left
In Words: With each trick, the number of biscuits decreases by 3.
Equation: b=-3t+23
Graph:

Practice makes perfect

The number of dog biscuits left is dependent on the number of tricks a dog performs. This means that the number of biscuits B is the dependent variable and the number of tricks t is the independent variable.

In Words

The relationship between the two variables can be stated in words as: With each trick performed, the number of biscuits decreases by 3.

Equation for the Relationship

Let's look for a pattern of change in the given table.

We can see that every time the t-values increase by 1, the B-values decrease by 3. This might lead us to believe that the relationship is just -3 times t. However, we can see that this does not work by checking any of the points. -3* t&? =B -3* 1&≠20 -3* 2&≠17 The values are 23 less than we need in each case. Therefore, we can say that the value of B is equal to -3 times t plus 23. We can write this as the following equation. B=-3t+23

Graphing the Relationship

To show our data graphically, we can plot the points on a coordinate plane. Notice that we cannot draw a line to represent this function because a dog cannot do a partial trick, so only whole numbers make sense in this context.