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Pearson Algebra 1 Common Core, 2011

PA

Pearson Algebra 1 Common Core, 2011 View details

Cumulative Standards Review

Exercise 13 Page 721

You will need to substitute 0 for y and solve.

C

Practice makes perfect

Think of the point where the graph of an equation intercepts the x-axis. The y-coordinate of this point is 0. Therefore, to find the x-intercept of a line, we need to substitute 0 for y in its equation.

-5x+y=- 20

y= 0

- 5x+ 0=- 20

Add terms

- 5x=- 20

.LHS /(- 5).=.RHS /(- 5).

x=4

An x-intercept of 4 means that the graph passes through the x-axis at the point ( 4,0). This result corresponds with choice C.

Subchapter links

Exercises p.720-722