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Now let's use a protractor.
The line of longitude that goes through point B is also perpendicular to the equator. To estimate the measure of the last angle, let's look at the ball from the top and use a protractor again.
The third angle in the triangle also has a measure of 90^(∘). This tells us that △ ABC has three right angles.
This time we choose lines of longitude that are not perpendicular. When we measure ∠ ACB we get that m∠ ACB= 60^(∘). Since the lines of longitude are perpendicular to the equator, we get that m∠ CAB=m∠ ABC=90^(∘). Let's create a triangle like below.
When we measure the angles of △ ABC, we get that m∠ ABC=75^(∘), m∠ BCA=45^(∘), and m∠ CAB=80^(∘). Now, let's tabulate the measures and record the sum of the measures of each triangle.
Triangle | Angles | Sum |
---|---|---|
1 | 90^(∘), 90^(∘), 90^(∘) | 270^(∘) |
2 | 90^(∘), 90^(∘), 60^(∘) | 240^(∘) |
3 | 75^(∘), 45^(∘), 80^(∘) | 200^(∘) |
Conjecture |
The sum of the measures of a triangle in spherical geometry is greater than 180^(∘). |