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McGraw Hill Integrated II, 2012

MH

McGraw Hill Integrated II, 2012 View details

8. Equations of Circles

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Exercise 16 Page 778

What is the standard form of an equation of a circle?

(x-8)^2+(y+9)^2=11

Practice makes perfect

Let's start by recalling the standard form of an equation of a circle.

(x- h)^2+(y- k)^2= r^2 In this form, ( h, k) is the center of the circle and r is its radius. We are told that the center of the circle is ( 8, - 9) and its radius is sqrt(11). This information is enough to write the equation. (x- 8)^2+(y-( - 9))^2=( sqrt(11))^2 ⇕ (x-8)^2+(y+9)^2=11

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Exercises p.778-781