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McGraw Hill Integrated II, 2012

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McGraw Hill Integrated II, 2012 View details

Practice Test

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Exercise 16 Page 86

Rewrite the given expression so that it is easier to make groups.

(a-5)(10a-1)

To factor by grouping, we will take the greatest common factor of the first pair of terms and the greatest common factor of the second pair of terms.

10a^2 - 50a-a+5

Factor out 10a

10a(a-5) - a + 5

Factor out - 1

10a(a-5)-1(a-5)

Notice that (a-5) is a factor of both terms, so we can factor it out.

10a(a-5)-1(a-5)

Factor out a-5

(a-5)(10a-1)

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