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Division by zero is not defined. This means that the denominator cannot be zero.
To graph the given rational function, we will find its domain, asymptotes, and intercepts. Then, we will find points using a table of values. Finally, we will plot and connect those points.
Consider the given function. f(x)=x^2-5x-14/x-7 Recall that division by zero is not defined. Therefore, the rational function is undefined where x-7=0. x-7=0 ⇔ x=7 This means that x=7 is not included in the domain. Domain All real numbers except x=7
Asymptotes can be vertical, horizontal, or oblique lines.
Let's consider the given function. f(x)=x^2-5x-14/x-7 Notice that the numerator can be factored. Let's factor this expression and cancel out any common factors between the numerator and the denominator.
Write as a sum
Factor out x
Factor out 2
Factor out (x-7)
We found that the denominator can be written as (x-7)(x+2). Let's use this to cancel common factors.
Cancel out common factors
Simplify quotient
We canceled out the factor x-7. Therefore, there is a hole in the graph at x=7. Since there are no other factors in the denominator, there are no vertical asymptotes.
To find the horizontal and oblique asymptotes, we can use a set of rules. To properly use these rules, in the following table, m and n are the degree of the numerator and denominator, respectively.
| f(x)=ax^m/bx^n | Asymptote | Asymptote Type |
|---|---|---|
| m | y=0 | Horizontal |
| m>n | none | - |
| m=n | y=a/b | Horizontal |
| m-n=1 | y= the quotient of the polynomials with no remainder | Oblique |
Now, consider the function one more time. Let's look at the degrees of the numerator and denominator for our function. f(x)=x^2-5x-14/x^1-7 We can see that the degree of the numerator is higher than the degree of the denominator. Therefore, there are no asymptotes.
The intercepts of the function are the points at which the graph intersects the axes.
The x-intercepts are the points where the graph intersects the x-axis. At these points, the value of the y-coordinate is zero. Let's substitute 0 for f(x) in the given function and solve for x.
By the Zero Product Property, the equation equals 0 when either of the factors is equal to 0. c|c x-7=0 & x+2=0 ⇕ & ⇕ x=7 & x=-2 We found that if f(x)=0, the value of x is 7 or -2. However, x=7 is not included in the domain of the function. Therefore, the only x-intercept occurs at the point (-2,0).
The y-intercept is the point where the graph intersects the y-axis. At this point, the value of the x-coordinate is zero. Let's substitute 0 for x in the given function and simplify.
x= 0
Identity Property of Addition
Cancel out common factors
Simplify quotient
There is a y-intercept at (0,2).
Let's make a table of values to graph the given function. Make sure to only use values included in the domain of the function.
| x | x^2-5x-14/x-7 | f(x)=x^2-5x-14/x-7 |
|---|---|---|
| 1 | 1^2-5( 1)-14/1-7 | 3 |
| 5 | 5^2-5( 5)-14/5-7 | 7 |
Finally, let's plot and connect the points. Do not forget to plot the intercepts and hole.