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When solving a rational equation we multiply each side of the equation by the least common multiple of the denominators. Use the factors of the given expression to write the denominators of your equation.
Example Solution: 1/x+3 + 1/x-4 = 1/4(x-4)
Let's begin by considering the following rational equation.
P_1(x)/Q_1(x) + P_2(x)/Q_2(x) = P_3(x)/Q_3(x)
Notice that this equation is just an example. We could have more terms on each side. When solving a rational equation, we multiply each side of the equation by the least common multiple of the denominators.
LCM(Q_1(x),Q_2(x),Q_3(x))
| Q_1(x) | Q_2(x) | Q_3(x) | |
|---|---|---|---|
| Combination 1 | x+3 | x-4 | 4(x-4) |
| Combination 2 | 4(x+3) | x-4 | x+3 |
| Combination 3 | 4 | x+3 | x-4 |
The above combinations are just a few. We can make many different combinations. Let's use the first one, and for simplicity consider all the numerators to be 1. 1/x+3 + 1/x-4 = 1/4(x-4) That way we have written a rational equation that can be solved by multiplying each side by 4(x+3)(x-4).
We already know the least common multiple of the denominators. We can multiply each side by it and then solve the resulting equation for x.
LHS * 4(x+3)(x-4)=RHS* 4(x+3)(x-4)
Multiply fractions
Cancel out common factors
Multiply
Add and subtract terms
LHS-x=RHS-x
LHS+4=RHS+4
.LHS /7.=.RHS /7.
Finally, let's check that x=1 is in fact a solution of our equation.
x= 1
Add and subtract terms
Multiply
LHS * (-12)=RHS* (-12)
Add terms
We got a true statement. Therefore, x=1 is a solution of our equation.