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The units of two quantities being equalized must be of the same dimension.
We can use dimensional analysis to see if the units of two quantities being equalized match their dimensions.
Then we are asked to find the radius of a sphere with a volume of 300 m^3. For this problem, we solve for the radius and obtain a relation. r = sqrt(3/4V) If we are not sure if we isolated correctly, we can check by analyzing the units on both sides of the equation. These must be the of the same dimension. We know the radius has dimensions of length; in this case, m and the volume have dimensions of length cubed m^3, while the constant 34 is adimensional. r = sqrt(3/4V) → m ≠ sqrt(m^3) As their dimensions do not match, this equation is dimensionally incorrect and does not make sense. This suggests we did a mistake while isolating r.